A building needs a ramp to make it handicap accessible. By law, the ramp must run 10 inches horizontally for every 1 inch of rise. If the surface of the ramp is 57 inches long how far above the ground is the inclined end of the ramp? Round to the nearest tenth of an inch.

Answer:The inclined end of the ramp is 5.7 in above the groundStep-by-step explanation:step 1we know thatThe ramp must run 10 inches horizontally for every 1 inch of riseApplying the Pythagoras Theorem, find the hypotenuse[tex]d^{2}=10^{2}+1^{2}[/tex][tex]d^{2}=101[/tex][tex]d=\sqrt{101}\ in[/tex]step 2Using proportion find out the height of the rampLetx ----> the height of the ramp[tex]\frac{x}{57}=\frac{1}{\sqrt{101}} \\ \\x=\frac{57}{\sqrt{101}}\\ \\x=5.7\ in[/tex]